Solved lab-javascript-basic-algorithms

index.html

@@ -11,6 +11,6 @@ <h1>LAB | JS Basic Algorithms</h1>
     <br />
     <p> Open the <a href="https://developer.chrome.com/docs/devtools/open/">Dev Tools console</a> to see the console output.</p>
 
-    <script src="index.js"></script>
+    <script src="./index.js"></script>
 </body>
 </html>

index.js

@@ -1,7 +1,83 @@
 // Iteration 1: Names and Input
+let hacker1 = "Maria";  
+console.log("The driver's name is " + hacker1);
 
+let hacker2 = "John";   
+console.log("The navigator's name is " + hacker2);
 
 // Iteration 2: Conditionals
-
+if (hacker1.length > hacker2.length) {
+  console.log("The driver has the longest name, it has " + hacker1.length + " characters.");
+} else if (hacker2.length > hacker1.length) {
+  console.log("It seems that the navigator has the longest name, it has " + hacker2.length + " characters.");
+} else {
+  console.log("Wow, you both have equally long names, " + hacker1.length + " characters!");
+}
 
 // Iteration 3: Loops
+console.log(hacker1.toUpperCase().split("").join(" "));  
+console.log(hacker2.split("").reverse().join(""));       
+
+// 3.3 Lexicographic order
+if (hacker1 < hacker2) {
+  console.log("The driver's name goes first.");
+} else if (hacker1 > hacker2) {
+  console.log("Yo, the navigator goes first, definitely.");
+} else {
+  console.log("What?! You both have the same name?");
+}
+
+// Bonus 1:
+let longText = `Lorem ipsum dolor sit amet, consectetur adipiscing elit. 
+Etiam et sapien euismod, et facilisis nunc ultrices. 
+Pellentesque habitant morbi tristique senectus et netus et malesuada fames ac turpis egestas.`;
+
+let words = 0;
+for(let i = 0; i < longText.length; i++) {
+  if (longText[i] === " " || longText[i] === "\n"){
+    words++;
+  }
+}
+words += 1;
+console.log("Number of words:", words);
+
+let etCount = 0;
+let textLower = longText.toLowerCase();
+
+for (let i = 0; i < textLower.length - 1; i++) {
+  if (textLower[i] === "e" && textLower[i+1] === "t") {
+    let before = (i === 0) ? " " : textLower[i-1];
+    let after = (i+2 >= textLower.length) ? " " : textLower[i+2];
+    if ((before === " " || before === "\n" || before === "," || before === ".") &&
+        (after === " " || after === "\n" || after === "," || after === ".")) {
+      etCount++;
+    }
+  }
+}
+
+console.log("Number of 'et' occurrences:", etCount);
+
+// Bonus 2
+let phraseToCheck = "A man, a plan, a canal, Panama!";
+
+let normalized = "";
+for (let i = 0; i < phraseToCheck.length; i++) {
+  let char = phraseToCheck[i].toLowerCase();
+  if (char >= "a" && char <= "z") {
+    normalized += char;
+  }
+}
+
+let isPalindrome = true;
+for (let i = 0; i < normalized.length / 2; i++) {
+  if (normalized[i] !== normalized[normalized.length - 1 - i]) {
+    isPalindrome = false;
+    break;
+  }
+}
+
+if (isPalindrome) {
+  console.log("The phrase is a palindrome!");
+} else {
+  console.log("The phrase is NOT a palindrome.");
+}