diff --git a/index.js b/index.js
index 6b0fec3ad..0fb17d44a 100644
--- a/index.js
+++ b/index.js
@@ -1,7 +1,75 @@
 // Iteration 1: Names and Input
+const hacker1="Danilo";
+console.log(`The driver's name is ${hacker1}`);
 
+const hacker2="Eugénie";
+console.log(`The navigator's name is ${hacker2}`);
 
 // Iteration 2: Conditionals
+const driverLength = hacker1.length;
+const navigatorLength = hacker2.length;
+
+if (driverLength > navigatorLength) {
+  console.log(`The driver has the longest name, it has ${driverLength} characters.`);
+} else if (navigatorLength > driverLength) {
+  console.log(`It seems that the navigator has the longest name, it has ${navigatorLength} characters.`);
+} else {
+  console.log(`Wow, you both have equally long names, ${driverLength} characters!`);
+}   
 
 
 // Iteration 3: Loops
+console.log(hacker1.toUpperCase().split('').join(' '));
+
+let reversedNavigator = '';
+for (let i = hacker2.length - 1; i >= 0; i--) {
+  reversedNavigator += hacker2[i];
+}
+console.log(reversedNavigator);
+
+
+if (hacker1 < hacker2) {
+  console.log("The driver's name goes first.");
+} else if (hacker2 < hacker1) {
+  console.log("Yo, the navigator goes first, definitely.");
+} else {
+  console.log("What?! You both have the same name?");
+}
+
+// Bonus 1:
+const loremIpsum = "Lorem ipsum dolor sit amet, consectetur adipiscing elit. Sed do eiusmod tempor incididunt ut labore et dolore magna aliqua.";
+const wordCount = loremIpsum.split(' ').length;
+console.log(`The Lorem Ipsum text contains ${wordCount} words.`);
+
+const etCount = (loremIpsum.match(/et/g) || []).length;
+console.log(`The word "et" appears ${etCount} times in the Lorem Ipsum text.`);
+
+// Bonus 2: 
+   const phraseToCheck = "A man, a plan, a canal, Panama!";
+
+function isPalindrome(str) {
+  let cleaned = '';
+  for (let i = 0; i < str.length; i++) {
+    const char = str[i];
+    if ((char >= 'a' && char <= 'z') || (char >= 'A' && char <= 'Z') || (char >= '0' && char <= '9')) {
+      if (char >= 'A' && char <= 'Z') {
+        cleaned += String.fromCharCode(char.charCodeAt(0) + 32);
+      } else {
+        cleaned += char;
+      }
+    }
+  }
+  const len = cleaned.length;
+  for (let i = 0; i < len / 2; i++) {
+    if (cleaned[i] !== cleaned[len - 1 - i]) {
+      return false;
+    }
+  }
+  return true;
+}
+
+if (isPalindrome(phraseToCheck)) {
+  console.log(`"${phraseToCheck}" is a palindrome.`);
+} else {
+  console.log(`"${phraseToCheck}" is not a palindrome.`);
+}                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                   
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